Given n=160
p=1.4%=0.014
As p is very small and n is large enough that is greater than 20, poisson approximation can be used and the parameter for poisson distribution would be
So now to find the probability of atmost 1 defective CD player that is there can be either 0 or 1 defective CD player among the 160 CD players
Let X be number of defective CD player, and x follows poisson distribution with mean 2.24
therfore the probability that there is atmost 1 defective CD player is 0.344917.
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