Statistics questions.
Given a data set with n trials (n=12), how do I calculate the 99.7% confidence level?
How do I calculate the uncertainty to a 99.7% confidence level?
How do I calculate average error? Comment how the 99.7% confidence levels compares to the average error..
1.
here z for 99.7% is 3 and n=12
confidence interval : [ mean - 3*SD/ 3.46 , mean + 3*SD/ 3.46 ]
{SD = standard deviation}
uncertainty = (100-99.7)/100 = 0.3/100 = 0.003
uncertainty = 0.003
average error :
here x = mean , xi = i th observation , n=12
check if z*(SD)/(n^0.5) = 3*(SD)/3.46
if [ 3*(SD)/3.46 ] is less than AE then we can say average error is covered in the confidence interval otherwise not
P.S. (please upvote if you find the answer satisfactory)
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