Question

The lifetime of TV is normal distributed with a mean of 4000 hours and standard deviation...

The lifetime of TV is normal distributed with a mean of 4000 hours and standard deviation of 250. Kyle told us that the z-score for his TV’s lifetime is 1.85. Calculate the lifetime of Kyle’s TV. (Round to 1 decimal places).

Homework Answers

Answer #1

Solution:
Given in the question
Lifetime of TV is normal distributed with
Mean() = 4000 hours
Standard deviation ()= 250 hours
Z-score for his TV's lifetime = 1.85
So Lifetime of Kyle's Tv can be calculated as
Lifetime of Kyle's TV = + Z-score* = 4000 + 1.85*250 = 4000 + 462.5 = 4462.5
So Lifetime of kyle's Tv is 4462.5 hours

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Suppose that the lifetimes of TV tubes are normally distributed with a standard deviation of 1.1...
Suppose that the lifetimes of TV tubes are normally distributed with a standard deviation of 1.1 years. Suppose also that exactly 40% of the tubes die before 5 years. Find the mean lifetime of TV tubes. Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place.
The lifetime of a certain type of battery is normally distributed with mean value 13 hours...
The lifetime of a certain type of battery is normally distributed with mean value 13 hours and standard deviation 1 hour. There are nine batteries in a package. What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages? (Round your answer to two decimal places.) hours
The lifetime of a certain type of battery is normally distributed with mean value 11 hours...
The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. There are nine batteries in a package. What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages? (Round your answer to two decimal places.) hours
The lifetime of a certain type of battery is normally distributed with mean value 11 hours...
The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. There are four batteries in a package. What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages? (Round your answer to two decimal places.)
The lifetime of lightbulbs produced is normally distributed with mean 500 hours and standard deviation 50...
The lifetime of lightbulbs produced is normally distributed with mean 500 hours and standard deviation 50 hours. What is the probability that a randomly chosen lightbulb will last between 440 and 620 hours?
The lifetime of a lightbulb follows a normal distribution with mean 1500 hours and standard deviation...
The lifetime of a lightbulb follows a normal distribution with mean 1500 hours and standard deviation of 100 hours. a. What is the probability that a lightbulb will last at least 1400 hours? b. What is the probability that a light bulb burns out in fewer than 1600 hours? c. What is the probability that a light bulb burns out in fewer than 1600 hours given that it has lasted 1400 hours? d. A technology breakthrough has occurred for which...
Q1-. A normal distribution has a mean of 15 and a standard deviation of 2. Find...
Q1-. A normal distribution has a mean of 15 and a standard deviation of 2. Find the value that corresponds to the 75th percentile. Round your answer to two decimal places. Q2-.Tyrell's SAT math score was in the 64th percentile. If all SAT math scores are normally distributed with a mean of 500 and a standard deviation of 100, what is Tyrell's math score? Round your answer to the nearest whole number. Q3-.Find the z-score that cuts off an area...
In a sample of 80 light bulbs, the mean lifetime was 1217 hours with a standard...
In a sample of 80 light bulbs, the mean lifetime was 1217 hours with a standard deviation of 53 hours. Find a 90% upper confidence interval for the mean lifetime. (Round the final answer to two decimal places.) The 90% upper confidence bound is ____ I got 1226.75, but it says it incorrect.
A normal population has a mean of 10.2 and a standard deviation of 1.4. Refer to...
A normal population has a mean of 10.2 and a standard deviation of 1.4. Refer to the table in Appendix B.1. a. Compute the z-value associated with 14.3. (Round the final answer to 2 decimal places.) z = b. What proportion of the population is between 10.2 and 14.3? (Round z-score computation to 2 decimal places and the final answer to 4 decimal places.) Proportion c. What proportion of the population is less than 10.0? (Round z-score computation to 2...
A normal population has a mean of 11.8 and a standard deviation of 4.6. Refer to...
A normal population has a mean of 11.8 and a standard deviation of 4.6. Refer to the table in Appendix B.1.   a. Compute the z-value associated with 14.3. (Round the final answer to 2 decimal places.) z =               b. What proportion of the population is between 11.8 and 14.3? (Round z-score computation to 2 decimal places and the final answer to 4 decimal places.) Proportion            c. What proportion of the population is less than 10.0?...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT