The salaries of teachers in the West Bloom Field Public School District are normally distributed with a mean of $53.5 thousand with a standard deviation of 5.5. What is the probability that a sample of 20 teachers will have a salary:
μ =53500
σ =5500
n= 20
Z=X-μ/(σ/√n)
A)
P(X>53500)
=P(z > 53500-53500/(5500/√20))
=P(z > 0)
=0.5 [standard normal distribution table]
B)
P( X < 50000)
= P( z < 50000-53500/(5500/√20))
=P(z < -2.84)
=0.5-0.4977 [standard normal distribution table]
=0.0023
C)
P(x > 55000)
=P( z > 55000-53500/(5500/√20))
=P(z > 1.22)
=0.5-0.3888 [standard normal distribution table]
=0.1112
D)
P(54000 < x < 55000)
=P( 54000 -53500/(5500/√20) < z < 55000-53500/(5500/√20) )
=P(0.41 < z < 1.22)
=0.3888 - 0.1591 [ standard normal distribution table]
=0.2297
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