Question

Mean 3407.94 Median 2364.00 Standard Deviation 3988.42 Minimum 136.00 Maximum 21451.00 n=52

Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 7000 in the United States and territories at the .05 level of significance.

1. Clearly state a null and alternative hypothesis
2. Give the value of the test statistic
3. Report the P-Value
4. Clearly state your conclusion (Reject the Null or Fail to Reject the Null)
5. Explain what your conclusion means in context of the data.

Answer 1

Claim:- average amount of marriages is greater or equal to 7000 in the United States and territories

Null hypothesis

Alternate hypothesis

test statistic =

degree of freedom = n-1 = 52 - 1 =51

using t distribution table with df(51) and t value(6.49), we get

p value = 0.0000

Rejecting the Null hypothesis as the p value is less than 0.05 significance level

We have sufficient evidence to warrant that the rejection of claim that average amount of marriages is greater or equal to 7000 in the United States and territories.