Calculate a Confidence Interval for the Mean, population standard deviation known - Calculator
Question
The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 15 people is selected at random, and the number of hours worked per year per person is given below. Calculate the 98% confidence interval for the mean hours worked per year in this state. Round your answers to the nearest integer and use ascending order.
Time |
2051 |
2061 |
2162 |
2167 |
2169 |
2171 |
2180 |
2183 |
2186 |
2195 |
2196 |
2198 |
2205 |
2210 |
2211 |
Solution:
The 98% confidence interval for population mean is given as follows:
Where,
is population standard deviation, n is sample size and Z(0.02/2) is critical z-value to construct 98% confidence interval.
We have, n = 15
Using Z-table we get, Z(0.02/2) = 2.3263
Hence, 98% confidence interval for the mean hours worked per year in the state is,
On rounding to nearest integer we get confidence interval as follows :
The 98% confidence interval for the mean hours worked per year in the state is (2146, 2193).
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