Question

In a random sample of four mobile devices, the mean repair cost was $65.00 and the standard deviation was $13.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results.

Answer #1

In a random sample of six mobile devices, the mean
repair cost was $60.00 and the standard deviation was $12.50.
Assume the population is normally distributed and use a
t-distribution to find the margin of error and construct a 99%
confidence interval for the population mean. Interpret the
results.
The 99% confidence interval for the population μ is (_, _)

In a random sample of six mobile devices, the mean repair cost
was $75.00 and the standard deviation was $13.0013.00. Assume the
population is normally distributed and use a t-distribution to
find the margin of error and construct a 95% confidence interval
for the population mean. Interpret the results.
The 95% confidence interval for the population mean μ is

In a random sample of four mobile devices, the mean repair cost
was $85.00 and the standard deviation was $12.00. Assume the
population is normally distributed and use a t-distribution to
find the margin of error and construct a 95% confidence interval
for the population mean. Interpret the results. The 95% confidence
interval for the population mean mu is ( ,). (Round to two
decimal places as needed.) The margin of error is $ nothing.
(Round to two decimal places...

In a random sample of 13 microwave ovens, the mean repair cost
was $70.00 and the standard deviation was $15.40.
Using the standard normal distribution with the appropriate
calculations for a standard deviation that is known, assume the
population is normally distributed, find the margin of error and
construct a 98% confidence interval for the population mean. A
98% confidence interval using the t-distribution was
(58.5,81.5).
Find the margin of error of the population mean.
Find the confidence interval of...

1) Use the given confidence interval to find the margin of error
and the sample mean. (12.8,19.8)
2) In a random sample of four microwave ovens, the mean repair
cost was $60.00 and the standard deviation was $12.00. Assume the
population is normally distributed and use a t-distribution to
construct a 99% confidence interval for the population mean ?.
What is the margin of error of ? Interpret the results.

in a random sample of 24 people, the mean commute time to work
was 33.7 minutes and the standard deviation was 7.1 minuets .
assume the population is normally distributed and use a
t-distribution to construct a 99% confidence interval for the
population mean. what is the margin of error of the mean? interpret
the results.

In a random sample of 22 people, the mean commute time to work
was 32.1 minutes and the standard deviation was 7.3 minutes. Assume
the population is normally distributed and use a t-distribution to
construct a 99% confidence interval for the population mean μ.
What is the margin of error of μ? Interpret the results.

In a random sample of 18 people, the mean commute time to work
was 32.4 minutes and the standard deviation was 7.2 minutes. Assume
the population is normally distributed and use a t-distribution to
construct a 99% confidence interval for the population mean mu.
What is the margin of error of mu? Interpret the results.

In a random sample of 28 people, the mean commute time to work
was 33.6 minutes and the standard deviation was 7.1 minutes. Assume
the population is normally distributed and use a t-distribution to
construct a 99% confidence interval for the population mean μ.
What is the margin of error of μ? Interpret the results.

In a random sample of five people, the mean driving distance to
work was 24.9 miles and the standard deviation was 4.3 miles.
Assuming the population is normally distributed and using the
t-distribution, a 99%confidence interval for the population mean
mu is left parenthesis 16.0 comma 33.8 right parenthesis (and the
margin of error is 8.9). Through research, it has been found that
the population standard deviation of driving distances to work is
3.3 Using the standard normal distribution with...

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