Question

Suppose a sitcom is filmed on set between zero and five days per week. The following...

Suppose a sitcom is filmed on set between zero and five days per week. The following table shows the probabilities of the sitcom being filmed zero, one, two, three, four, or five days in a week.

x P ( x )

0 = 0.11213

1 = 0.14558

2 = 0.16942

3 = 0.22547

4 = 0.15375

5 = 0.19365

The expected number of days the sitcom will be filmed in one week, μ , is 2.74408. Use the formula below to calculate the variance, σ 2 , of the number days the sitcom films, x , where P ( x ) is the probability of the sitcom filming for a particular number of days. σ 2 = ∑ [ ( x − μ ) 2 ⋅ P ( x ) ]

Provide each answer with three decimal places of precision.

What is the weighted probability of two days of filming?

What is the weighted probability of three days of filming?

What is the weighted probability of four days of filming?

What is the weighted probability of five days of filming?

What is the weighted probability of zero days of filming?

What is the weighted probability of one day of filming?

What is the variance?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Parts A-C: A)Let X be the number of successes in five independent trials of a binomial...
Parts A-C: A)Let X be the number of successes in five independent trials of a binomial experiment in which the probability of success is p = 3/5 Find the following probabilities. (Round your answers to four decimal places.). (1)    P(X = 4) _________ (2)    P(2 ≤ X ≤ 4)_________ B) Suppose X is a normal random variable with μ = 500 and σ = 72. Find the values of the following probabilities. (Round your answers to four decimal places.) (1)    P(X < 750)___________...
This week we study Normal Distribution. Part 1. Demonstrate that you understand basic concept of Normal...
This week we study Normal Distribution. Part 1. Demonstrate that you understand basic concept of Normal Distribution. In two small paragraphs describe a couple of properties/rules of Normal distribution. Give one example of some practical case where we can use Normal distribution (for instance, IQ scores follow a normal distribution of probabilities with the mean IQ of 100 and a standard deviation around the mean of about 15 IQ points.) Part 2. Assign your numbers for mean μ and standard...
A medical insurance plan reimburses $100 per day, up to a maximum of five days, for...
A medical insurance plan reimburses $100 per day, up to a maximum of five days, for each day the policy holder is hospitalized. It is estimated that the probability that any person is hospitalized for exactly one day is 0.001, for exactly two days is 0.002, for exactly three days is 0.003; for exactly four days is 0.004, and for five or more days 0.008. The annual premium is $10. (a) Construct the probability distribution for X, the number of...
Employers particularly want to know which days of the week employees are absent in a five-day...
Employers particularly want to know which days of the week employees are absent in a five-day work-week. Most employers would like to believe that employees are absent equally during the week. That is, the average number of times an employee is absent is the same on Monday, Tuesday Wednesday, Thursday, or Friday. Suppose a sample of 20 absent days was taken and the days absent were distributed as follows: Monday Tuesday Wednesday Thursday Friday Number of Absences 5 4 2...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders. x 0 1 2 3 4 5 P(x) 0.209 0.362 0.225 0.174 0.029 0.001 (a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders. x 0 1 2 3 4 5 P(x) 0.210 0.362 0.228 0.169 0.030 0.001 (a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders. x 0 1 2 3 4 5 P(x) 0.210 0.381 0.222 0.168 0.018 0.001 (a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders. x 0 1 2 3 4 5 P(x) 0.205 0.374 0.207 0.186 0.027 0.001 (a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders. x 0 1 2 3 4 5 P(x) 0.228 0.380 0.221 0.133 0.037 0.001 (a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders. x 0 1 2 3 4 5 P(x) 0.225 0.370 0.209 0.161 0.034 0.001 (a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT