Find the value of the standard normal random variable z, called z0 such that:
(a) P(z≤z0)=0.668 z0=
(b) P(−z0≤z≤z0)=0.4818 z0=
(c) P(−z0≤z≤z0)=0.4106 z0=
(d) P(z≥z0)=0.0773 z0=
(e) P(−z0≤z≤0)=0.2455 z0=
(f) P(−1.97≤z≤z0)=0.7388 z0=
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