If an ANOVA, with N = 50, produces a grand total of 300 (G = 300) and ΣX² = 2300, what is the SStotal?
a. -87700
b. 1800
c. 2300
d. 500
2.If η² for an ANOVA was 1 that would mean…
a. there was no treatment effect
b. the total variance = the within-treatment variance
c. there was no within-treatment variance
d. there was no difference between the means
3. If η² for an ANOVA was 0 that would mean…
a. |
the total variance = the between-treatment variance |
|
b. |
there was no error variance |
|
c. |
there was no difference between the means |
|
d. |
there was no within-treatment variance |
4.The F-ratio is communicating
a. |
The ratio of within-treatment variance to error variance |
|
b. |
The ratio of between-treatment variance to systematic variance |
|
c. |
The ratio of random variance to error variance |
|
d. |
The ratio of between-treatment variance to error variance |
5. A Post-Hoc test is done when
a. |
ANOVA with two or more groups retains the null |
|
b. |
ANOVA with two or more groups rejects the null |
|
c. |
ANOVA with three or more groups retains the null |
|
d. |
ANOVA with three or more groups rejects the null |
6. Compared to Tukey’s HSD, the Scheffe test is:
a. |
more likely to reject the null |
|
b. |
less likely to make a Type I Error |
|
c. |
more likely to make a Type I Error |
|
d. |
less likely to retain the null |
Ans:
1)
SST=2300-(300^2/50)
SST=500
2)
η²=SS(between)/SS(total)
η²=SS(between)/(SS(between)+SS(within))
Now if SS(within)=0
Then
η²=1
Correct option is:
there was no within-treatment variance
3)there was no difference between the means
)Correct option is:
the ratio of between-treatment variance to error variance
F=MS(between)/MS(error)
5)Correct option is:
ANOVA with three or more groups rejects the null
(when ANOVA results are significant)
6)the Scheffe test is less likely to make a Type I Error
(as type II error is higher for Scheffe's test)
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