If an ANOVA, with N = 50, produces a grand total of 300 (G = 300) and ΣX² = 2300, what is the SS_{total}?
a. 87700
b. 1800
c. 2300
d. 500
2.If η² for an ANOVA was 1 that would mean…
a. there was no treatment effect
b. the total variance = the withintreatment variance
c. there was no withintreatment variance
d. there was no difference between the means
3. If η² for an ANOVA was 0 that would mean…
a. 
the total variance = the betweentreatment variance 

b. 
there was no error variance 

c. 
there was no difference between the means 

d. 
there was no withintreatment variance 
4.The Fratio is communicating
a. 
The ratio of withintreatment variance to error variance 

b. 
The ratio of betweentreatment variance to systematic variance 

c. 
The ratio of random variance to error variance 

d. 
The ratio of betweentreatment variance to error variance 
5. A PostHoc test is done when
a. 
ANOVA with two or more groups retains the null 

b. 
ANOVA with two or more groups rejects the null 

c. 
ANOVA with three or more groups retains the null 

d. 
ANOVA with three or more groups rejects the null 
6. Compared to Tukey’s HSD, the Scheffe test is:
a. 
more likely to reject the null 

b. 
less likely to make a Type I Error 

c. 
more likely to make a Type I Error 

d. 
less likely to retain the null 
Ans:
1)
SST=2300(300^2/50)
SST=500
2)
η²=SS(between)/SS(total)
η²=SS(between)/(SS(between)+SS(within))
Now if SS(within)=0
Then
η²=1
Correct option is:
there was no withintreatment variance
3)there was no difference between the means
)Correct option is:
the ratio of betweentreatment variance to error variance
F=MS(between)/MS(error)
5)Correct option is:
ANOVA with three or more groups rejects the null
(when ANOVA results are significant)
6)the Scheffe test is less likely to make a Type I Error
(as type II error is higher for Scheffe's test)
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