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3. Assume that oak trees have an average height of 90 feet with a standard deviation...

3. Assume that oak trees have an average height of 90 feet with a standard

deviation of 14 feet. Their heights are normally distributed (i.e., μ = 90 and σ = 14).

A. Using a z table determine the percent of oak trees that are at least 106.50 feet tall. (Hint: You will need to start by converting 106.50 to a z score.)

B. Using a z table determine the percent of oak trees that are 83.95 feet or less.

C. Using your answers to A and B, what percent of oak trees’ heights are between 83.95 feet and 106.50 feet?

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