Question

A 6th grade teacher was interested in comparing two ways of teaching math to her students. She used method A with one of her existing classes and method B with another one. She flipped a coin to decide which class would receive method A. At the end of the year her students obtained the following scores (percent correct) on a comprehensive math exam. Method A: 75, 82, 88, 93, 69, 72, 78, 81, 84, 96 Method B: 66, 84, 72, 73, 93, 80, 77, 65, 88, 72

part A.

What was the mean score of students under method A?

part b

What was the mean score of students under method B?'

part c

1. What was the measurement scale for the math scores?

   		Nominal
   		Ordinal
   		Interval
   		Ratio

part d

Based on these means, the teacher concluded that method A was better than method B. Why might the teacher be wrong about her conclusions?

part e.

If the true population mean for method A is 81.8 with a variance of 76.84, and the true population mean for method B is 77 with a variance of 85.11, then what is the mean of the sampling distribution of the difference between the means of group A and B?

part f

If the true population mean for method A is 81.8 with a variance of 76.84, and the true population mean for method B is 77 with a variance of 85.11, then w hat is the standard error of this sampling distribution?

part g

How were students assigned to the different teaching methods?

Answer 1