Independent random samples of newly completed apartments in four regions of a country yielded the data on monthly rents, in dollars and the summary statistics is given below:
Region | n | Mean | Std.deviation |
MW | 6 | 752.33 | 89.37 |
NE | 5 | 1051 | 146.10 |
S | 4 | 862.25 | 159.37 |
W | 5 | 1055.60 | 122.62 |
Do the data provide sufficient evidence to conclude that a difference exists in mean monthly rents among newly completed apartments in the four regions?
A partially filled in ANOVA table is presented below
Source | SS | DF | MS | F |
Between | 359293.92 | |||
Within | XX | |||
Total | 620951.20 | XX | XX |
What is the value of the F critical value at the α=0.05α=0.05 level? Report 4 decimal places.
Source | SS | DF | MS | F |
Between | 359293.92 | 4 - 1 = 3 | 359293.92 / 3 = 119764.64 | 119764.64 / 16353.58 = 7.3234 |
Within | 620951.20 - 359293.92 = 261657.28 | 19 - 3 = 16 | 261657.28 / 16 = 16353.58 | XX |
Total | 620951.20 | 20 - 1 = 19 | XX | XX |
For critical value of F at α=0.05
F( 3, 16 ) at α=0.05 = 3.239
Do the data provide sufficient evidence to conclude that a difference exists in mean monthly rents among newly completed apartments in the four regions?
Since, F = 7.3234 > F( 3, 16 ) at α=0.05 = 3.239 therefore, we will reject the null hypothesis of equality
Yes, a difference exists in mean monthly rents among newly completed apartments in the four regions
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