Question

Randomly selected students were given five seconds to estimate the value of a product of numbers with the results shown below.

Estimates from students given 1×2×3×4×5×6×7×81×2×3×4×5×6×7×8:

200, 1500, 1000, 10000, 1560, 856, 200, 2040, 200, 45000

Estimates from students given 8×7×6×5×4×3×2×18×7×6×5×4×3×2×1:

550, 450, 500, 3500, 2000, 350, 400, 49000, 25000, 40320
Use a 0.050.05 significance level to test the claim that the two populations have the same mean.

(a) The test statistic is

Answer 1

using R

we have '

> x<-c(200, 1500, 1000, 10000, 1560, 856, 200, 2040, 200, 45000)
> y<-c(550, 450, 500, 3500, 2000, 350, 400, 49000, 25000, 40320)
> t.test(x,y,alternative = c("two.sided") ,var.equal =TRUE,conf.level = 0.95 )

   Two Sample t-test

data: x and y
t = -0.80466, df = 18, p-value = 0.4315
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-21490.104 9587.304
sample estimates:
mean of x mean of y
6255.6 12207.0

(a) The test statistic is -0.80466

p value is 0.4315 , since p value is gretaer than 0.05 so we will conclude that the two populations have the same mean.