Question

1. We wish to estimate what percent of adult residents in a
certain county are parents. Out of 400 adult residents sampled, 296
had kids. Based on this, construct a 95% confidence interval for
the proportion p of adult residents who are parents in this county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places.

__< p <__ Express the same answer using the point estimate
and margin of error. Give your answers as decimals, to three
places.

p =__ ±±____

2.

Giving a test to a group of students, the grades and gender are summarized below

A | B | C | Total | |

Male | 14 | 8 | 15 | 37 |

Female | 13 | 18 | 12 | 43 |

Total | 27 | 26 | 27 | 80 |

Let p represent the population proportion of all female students
who received a grade of C on this test. Use a 95% confidence
interval to estimate p to four decimal places if possible.

___< p < ____

3. Assume that a sample is used to estimate a population
proportion *p*. Find the 99% confidence interval for a
sample of size 308 with 136 successes. Enter your answer as an
**open-interval** (*i.e.*, parentheses) using
decimals (not percents) accurate to three decimal places.

C.I. =_____

4. Assume that a sample is used to estimate a population
proportion *p*. Find the 90% confidence interval for a
sample of size 276 with 36% successes. Enter your answer as a
tri-linear inequality using decimals (not percents) accurate to
three decimal places.

__ < *p* <___

Answer #1

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 400 adult residents sampled, 128 had
kids. Based on this, construct a 99% confidence interval for the
proportion p of adult residents who are parents in this
county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places.
____ < p < ____ Express the same answer using the point
estimate and margin of error. Give your answers as...

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 500 adult residents sampled, 235 had
kids. Based on this, construct a 99% confidence interval for the
proportion p of adult residents who are parents in this county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places. < p < Express the same answer
using the point estimate and margin of error. Give your answers as
decimals, to...

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 100 adult residents sampled, 40 had
kids. Based on this, construct a 95% confidence interval for the
proportion p of adult residents who are parents in this
county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places.
< p < Express the same answer using the point
estimate and margin of error. Give your answers as decimals, to
three...

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 500 adult residents sampled, 360 had
kids. Based on this, construct a 90% confidence interval for the
proportion p of adult residents who are parents in this county.
Give your answers as decimals, to 4 places. Answer = ± (Note this
is NOT in interval form, so check your answer carefull

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 400 adult residents sampled, 156 had
kids. Based on this, construct a 95% confidence interval for the
proportion ππ of adult residents who are parents in this
county.
Give your answers as decimals, to three places

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 600 adult residents sampled, 270 had
kids. Based on this, construct a 90% confidence interval for the
proportion p p of adult residents who are parents in this
county.

1. If n=290 and X = 232, construct a 99% confidence
interval.
Enter your answer as an open-interval
(i.e., parentheses) using decimals (not percents) accurate
to three decimal places.
Confidence interval =
Express the same answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.
< p <
Express the same answer using the point estimate and margin of
error. Give your answers as decimals, to three places.
p = ±±
2. We wish to estimate...

We
wish to estimate what percent of adult residents in a certain
county are parents. Out of 500 adult residents sampled, 400 had
kids. Based on this , construct a 90% confidence interval for the
proportion of sdult residents who are parents in this
country.

1. A poll of 2234 U.S. adults found that 31% regularly used
Facebook as a news source.
Find the margin of error and confidence interval for the
percentage of U.S. adults who regularly use Facebook as a news
source, at the 90% level of confidence. Round
all answers to 2 decimal places.
Margin of Error (as a percentage):
Confidence Interval: % to %
Find the margin of error and confidence interval for the
percentage of U.S. adults who regularly use...

Assume that a sample is used to estimate a population proportion
p. Find the 99% confidence interval for a sample of size
288 with 143 successes. Enter your answer as a tri-linear
inequality using decimals (not percents) accurate to three decimal
places.
_____< p < ______

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