Question

The partially complete ANOVA table given here is for a two-factor factorial experiment Source   Df SS...

The partially complete ANOVA table given here is for a two-factor factorial experiment

Source

  Df

SS

MS

factor A

3

2.25

0.75

Factor B

1

0.95

Interaction

3

0.30

error

16

2.40

0.15

total

6.50

The number of observations collected for this study is  

The Sum of Squares for the interaction is equal to

The Sum of Squares for the treatments is equal to

The number of degrees of freedom for the treatments is equal to

The Mean of Squares for factor B is equal to

The F-test for interaction effect is equal to

The rejection region at alpha 0.01 for the test of significance of the interaction is equal to

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The partially complete ANOVA table given here is for a two-factor factorial experiment Source Df SS...
The partially complete ANOVA table given here is for a two-factor factorial experiment Source Df SS MS factor A 3 2.25 0.75 Factor B 1 0.95 0 Interaction 3 0  0.30 error 16 2.40 0.15 total 0 6.50 0 the number of observations collected for this study is ____ The Sum of Squares for the interaction is equal to _______ The Sum of Squares for the treatments is equal to _______ The number of degrees of freedom for the treatments is...
Consider the following partially completed two-way ANOVA table. Suppose there are 2 levels of Factor A...
Consider the following partially completed two-way ANOVA table. Suppose there are 2 levels of Factor A and 3 levels of Factor B. The number of replications per cell is 3. Use the 0.01 significance level. (Hint: estimate the values from the F table.) Source SS df MS F Factor A 525 Factor B 60 Interaction 325 Error 625 Total 1,535 Complete an ANOVA table. (Round MS and F to 2 decimal places.) Find the critical values to test for equal...
Consider the partial ANOVA table shown below. Let a = .01 Source of Variation DF SS...
Consider the partial ANOVA table shown below. Let a = .01 Source of Variation DF SS MS F Between Treatments 3 180 Within Treatments (Error) Total 19 380 If all the samples have five observations each: there are 10 possible pairs of sample means. the only appropriate comparison test is the Tukey-Kramer. all of the absolute differences will likely exceed their corresponding critical values. there is no need for a comparison test – the null hypothesis is not rejected. 2...
The calculations for a factorial experiment involving four levels of factor A, three levels of factor...
The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following data: SST= 248, SSA= 22, SSB= 21, SSAB= 155. Set up the ANOVA table and test for significance using alpha= .05 . Show entries to 2 decimals, if necessary. If the answer is zero enter “0”. Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Factor A Factor B Interaction Error Total
ANOVA Source of Variation SS df MS F p-value Factor A 31,313.49 3 10,437.83 Factor B...
ANOVA Source of Variation SS df MS F p-value Factor A 31,313.49 3 10,437.83 Factor B 23,456.13 2 11,728.07 Interaction 163,204.45 6 27,200.74 Error 90,156.59 36 2,504.35 Total 308,130.66 47 (a) What kind of ANOVA is this? One-factor ANOVA Two-factor ANOVA with replication Two-factor ANOVA without replication (b) Calculate each F test statistic and the p-value for each F test using Excel's function =F.DIST.RT(F,DF1,DF2). (Round your Fcalc values to 3 decimal places and p-values to 4 decimal places.) Source of...
ANOVA summary table. A partially completed ANOVA tale for a competely randomized design is shown here....
ANOVA summary table. A partially completed ANOVA tale for a competely randomized design is shown here. Source df SS MS F Treatments Error 4 - 24.7 Total 34 62.4 (a) Complete the ANOVA table. (b) How many treatments are involved in the experiment? (c) Do the data provide sufficient evidence to indicate a difference among the treatment means? Test using α = .10.
Consider the partially completed ANOVA summary table below. Complete parts a through d below. Source df...
Consider the partially completed ANOVA summary table below. Complete parts a through d below. Source df SS MS F Regression 1 700 Residual Total 9 1000 a. Complete the remaining entries in the table. Source df SS MS F Regression 1 700 nothing nothing Residual nothing nothing nothing Total 9 1000 ​(Type integers or decimals rounded to two decimal places as​ needed.) b. How many ordered pairs are in this​ sample? c. Calculate the sample coefficient of determination. d. Using...
Consider the partially completed one-way ANOVA summary table. Source SS df MS F Treatment 150 Error...
Consider the partially completed one-way ANOVA summary table. Source SS df MS F Treatment 150 Error 17 Total 840 21 Using α = 0.05, the critical F-score for this ANOVA procedure is ________.
The following ANOVA table was obtained from a balanced completely randomized design: Source df SS MS...
The following ANOVA table was obtained from a balanced completely randomized design: Source df SS MS F Treatment 126 Error 20 16 Total 23 Fill in the blanks in this table. Determine the number of treatments. Determine the number of replications per treatment. Perform a statistical test to see if there is a difference between the true mean responses to the treatment.
complete the ANOVA table below. Assume α = 0.05. fill in the blanks what is the...
complete the ANOVA table below. Assume α = 0.05. fill in the blanks what is the p-value for the factor Source of Variation Degrees of freedom Sum of Squares (SS) Mean Squares (MS) F Test Statistic P-Value Factor 57258 Error 1289 XXXXX XXXXX Total 37 101094 XXXXX XXXXX XXXXX
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT