The standard IQ test has a mean of 97 and a standard deviation of 17. We want to be 95% certain that we are within 5 IQ points of the true mean. Determine the required sample size.
Solution :
Given that,
standard deviation = = 77
margin of error = E = 5
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Sample size = n = ((Z/2 * ) / E)2
= ((1.960 * 17) / 5)2
= 44.40
= 44
Sample size = 44
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