Create a sample space for having four children. Then, find the probability that when a couple has four children, there are exactly two boys.
Solution:
Part a) Create a sample space for having four children.
4 Boys | 3 Boys 1 Girl | 2 Boys 2 Girls | 1 Boy 3 Girls | 4 Girls |
---|---|---|---|---|
BBBB | BBBG | BBGG | BGGG | GGGG |
BBGB | BGBG | GBGG | ||
BGBB | GBBG | GGBG | ||
GBBB | GBGB | GGGB | ||
GGBB | ||||
BGGB |
We can write collectively as follows:
S = { BBBB, BBBG, BBGB, BGBB, GBBB, BBGG, BGBG, GBBG, GBGB, GGBB, BGGB, BGGG, GBGG, GGBG, GGGB, GGGG}
n = Total outcomes = 16
Part b) find the probability that when a couple has four children, there are exactly two boys.
P( exactly two boys ) =.............?
exactly two boys = { BBGG, BGBG, GBBG, GBGB, GGBB, BGGB }
m = Number of outcomes for exactly two boys = 6
Thus
P( exactly two boys ) = m / n
P( exactly two boys ) = 6 / 16
P( exactly two boys ) = 3 / 8
P( exactly two boys ) = 0.375
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