It is desired to estimate the proportion of female students at a certain university. At a confidence level of 92%, determine the minimum sample size to ensure that the margin of error in your point estimate is no greater than 8%.
Solution :
Given that,
= 0.5 ( when estimate is not given than use 0.50
1 - = 1 - 0.5 = 0.5
margin of error = E = 8% = 0.08
At 92% confidence level the z is ,
= 1 - 92% = 1 - 0.92 = 0.08
/ 2 =0.04
Z/2 = Z0.04 = 1.751
Sample size = n = (Z/2 / E)2 * * (1 - )
= (1.751 / 0.08)2 * 0.5 * 0.5
= 120
Sample size = 120
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