(1 point) An Office of Admission document at a certain university claims that 55.6% of their undergraduates are female. To test this claim, a random sample of 235 undergraduates was selected. In this sample, 55.3% were female. Is there sufficient evidence to conclude that the document's claim is false? Carry out a hypothesis test at a 1% significance level.
A. The value of the test statistic is:
B. The p-value is
D. Your decision for the hypothesis test:
A. Do Not Reject ?1H1.
B. Do Not Reject ?0H0.
C. Reject ?1H1.
D. Reject ?0H0.
Solution :
This is the two tailed test .
The null and alternative hypothesis is
H0 : p = 0.556
Ha : p 0.556
= 0.553
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
= 0.553 - 0.556 / [(0.556 * 0.444) / 235]
= -0.09
P-value = 0.9262
= 0.01
P-value >
Do not eject the H0
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