Question

Question:  Decide between the null and alternative hypotheses and state a real world conclusion. Data were collected...

Question:  Decide between the null and alternative hypotheses and state a real world conclusion.

Data were collected from a random sample of American Facebook accounts. Data concerning gender and number of Facebook friends:

Descriptive Statistics

Sample

N

Mean

StDev

SE Mean

Men

64

717.56

530.40

66.30

Woman

66

618.95

454.16

55.90

Test

Null hypothesis

H₀: μ₁ - μ₂ = 0

Alternative hypothesis

H₁: μ₁ - μ₂ ≠ 0

T-Value

DF

P-Value

1.14

123

0.2577

Homework Answers

Answer #1

Given,

Null hypothesis : Ho : ; Difference in the average number of facebook friends between men and women is zero

Alternate Hypothesis : H1 : Difference in the average number of facebook friends between men and women is not zero

Assumed :0.05

As p-value : 0.2577 is greater than : 0.05 ; Fail to reject null hypothesis.

There is not sufficient evidence to conclude that the Difference in average number of facebook friends between men and women is not zero

For that matter even if =0.01 also,

As p-value : 0.2577 is greater than : 0.01 ; Fail to reject null hypothesis.

There is not sufficient evidence to conclude that the Difference in average number of facebook friends between men and women is not zero

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For this assignment, use data from W1 Midweek Assignment. Using Minitab Express, compute a one-sample t-test...
For this assignment, use data from W1 Midweek Assignment. Using Minitab Express, compute a one-sample t-test comparing the age of your sample to the age of the general population of college students in traditional on-ground universities. Assume the population mean is 21. Move your output into a Microsoft Word document and write a 1-paragraph, APA-formatted interpretation of the results. My data output from minitab is: Descriptive Statistics N Mean StDev SE Mean 95% CI for μ 40 20.9750 2.1542 0.3406...
I. State null and alternative hypotheses. II. Decide on the significance level, α. III. Compute the...
I. State null and alternative hypotheses. II. Decide on the significance level, α. III. Compute the value of the test statistic. IV. Determine the critical value(s). V. If the value of the test statistic falls in the rejection region, reject H0. VI. Interpret the result of the hypothesis test. Question: . A manufacturer claims that the thickness of the spearmint gum it produces is 7.5 one-hundredths of an inch. A quality control specialist regularly checks this claim. On one production...
Identify the null and alternative hypothesis(in symbolic and sentence form), test statistic, P-value(or critical values), conclusion...
Identify the null and alternative hypothesis(in symbolic and sentence form), test statistic, P-value(or critical values), conclusion about the null hypothesis, and final conclusion that addresses the original claim (Don’t just say Reject the null hypothesis or fail to reject the null hypothesis). 3. Test the claim that for the population of female college students, the mean weight is given by μ=132 lb Sample data are summarized as n=20,x ̅=137lb and s=14.2. Use a significance level of α=0.10.
Suppose you have the following null and alternative hypotheses: H0: μ = 81 and H1: μ...
Suppose you have the following null and alternative hypotheses: H0: μ = 81 and H1: μ ≠ 81. You collect a sample of data from a population that is normally distributed . The sample size is 19, the sample mean is 84.9, and the population standard deviation is 5.7. What is your p-value and conclusion? Test at a level of significance of 0.01. A. 0.0080, Do Not Reject B. 0.0029, Reject C. 0.0029, Do Not Reject D. 0.0064, Reject E....
To perform a test of the null and alternative hypotheses shown below, random samples were selected...
To perform a test of the null and alternative hypotheses shown below, random samples were selected from the two normally distributed populations with equal variances. The data are shown below. Test the null hypothesis using an alpha level equal to 0.10. Sample from Population 1: 38,28,28,39,39,33,29,37,43,38 Sample from Population 2: 45,53,37,47,44,38,43,46,46,41 H0: ?1 ? ?2 = 0 HA: ?1 – ? ? 0 Determine the rejection region for the test statistic t. Select the correct choice below and fill in...
I. State null and alternative hypotheses. II. Decide on the significance level, α. III. Compute the...
I. State null and alternative hypotheses. II. Decide on the significance level, α. III. Compute the value of the test statistic. IV. Determine a p-value, P. V. If P ≤ α reject H0, otherwise do not reject H0. VI. Interpret the result of the hypothesis test. 6. A biologist was interested in determining whether specific seedlings treated with a new fertilizer resulted in a higher than average height than the standard height of 11.2 cm. The biologist treated a random...
Conduct a test at the alphaequals0.10 level of significance by determining ​(a) the null and alternative​...
Conduct a test at the alphaequals0.10 level of significance by determining ​(a) the null and alternative​ hypotheses, ​(b) the test​ statistic, and​ (c) the​ P-value. Assume the samples were obtained independently from a large population using simple random sampling. Test whether p 1 greater than p 2. The sample data are x 1 equals 123​, n 1 equals 248​, x 2 equals 141​, and n 2 equals 312. ​(a) Choose the correct null and alternative hypotheses below. A. Upper H...
The table below summarizes data from a survey of a sample of women. Using a 0.050.05...
The table below summarizes data from a survey of a sample of women. Using a 0.050.05 significance​ level, and assuming that the sample sizes of 900900 men and 400400 women are​ predetermined, test the claim that the proportions of​ agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does it appear that the gender of the interviewer affected the responses of​ women? Gender of Interviewer Man Woman Women who agree 572 336 Women...
Method Null hypothesis H₀: All means are equal Alternative hypothesis H₁: At least one mean is...
Method Null hypothesis H₀: All means are equal Alternative hypothesis H₁: At least one mean is different Equal variances were assumed for the analysis. Factor Information Factor Levels Values StressLevel 3 High, Low, Medium Analysis of Variance Source DF Adj SS Adj MS F-Value P-Value StressLevel 2 261.361 130.681 18.76 <0.0001 Error 69 480.583 6.965 Total 71 741.944 Model Summary S R-sq R-sq(adj) R-sq(pred) 2.63912 35.23% 33.35% 29.47% Means StressLevel N Mean StDev 95% CI High 24 5.2083 2.6536 (4.1336,...
The blue catfish (Ictalurus Furcatus) is the largest species of North American catfish. The current world...
The blue catfish (Ictalurus Furcatus) is the largest species of North American catfish. The current world record stands at 143 pounds, which was caught in the John H. Kerr Reservoir (Bugg's Island Lake) located in Virginia. According to American Expedition, the average weight of a blue catfish is between 20 to 40 pounds. Given that the largest blue catfish ever caught was at the John H. Kerr Reservoir, you believe that the mean weight of the fish in this reservoir...