Question

The director of library services at a college did a survey of types of books (by...

The director of library services at a college did a survey of types of books (by subject) in the circulation library. Then she used library records to take a random sample of 888 books checked out last term and classified the books in the sample by subject. The results are shown below.

Subject Area

Percent of Books on Subject in Circulation

Library on This Subject

Number of Books in

Sample on This Subject

Business

32%

283

Humanities

25%

215

Natural Science

20%

220

Social Science

15%

102

All other subjects

8%

68

Using a 5% level of significance, test the claim that the subject distribution of books in the library fits the distribution of books checked out by students.

(a) What is the level of significance?

State the null and alternate hypotheses.

H0: The distributions are the same.

H1: The distributions are the same.

H0: The distributions are different.

H1: The distributions are different.   

H0: The distributions are different.

H1: The distributions are the same.

H0: The distributions are the same.

H1: The distributions are different.

(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to three decimal places. Round the test statistic to three decimal places.)

Are all the expected frequencies greater than 5?

Yes

No    

What sampling distribution will you use?

chi-square

uniform    

binomial

normal

Student's t

What are the degrees of freedom?

(c) Estimate the P-value of the sample test statistic.

P-value > 0.100

0.050 < P-value < 0.100    

0.025 < P-value < 0.050

0.010 < P-value < 0.025

0.005 < P-value < 0.010

P-value < 0.005

(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of independence?

Since the P-value > α, we fail to reject the null hypothesis.

Since the P-value > α, we reject the null hypothesis.    

Since the P-value ≤ α, we reject the null hypothesis.

Since the P-value ≤ α, we fail to reject the null hypothesis.

(e) Interpret your conclusion in the context of the application.

At the 5% level of significance, the evidence is sufficient to conclude that the subject distribution of books in the library is different from that of books checked out by students.

At the 5% level of significance, the evidence is insufficient to conclude that the subject distribution of books in the library is different from that of books checked out by students.

Homework Answers

Answer #1

a)

level of significance =0.05
Ho: the distributions are the same
H1: the distributions are different

b)applying chi square test:

           relative observed Expected residual Chi square
category frequency(p) Oi Ei=total*p R2i=(Oi-Ei)/√Ei R2i=(Oi-Ei)2/Ei
1 0.320 283.000 284.160 -0.07 0.005
2 0.250 215.000 222.000 -0.47 0.221
3 0.200 220.000 177.600 3.18 10.123
4 0.150 102.000 133.200 -2.70 7.308
5 0.080 68.000 71.040 -0.36 0.130
total 1.000 888 888 17.7862
value of the chi-square statistic =17.786
Are all the expected frequencies greater than 5? :Yes
What sampling distribution will you use? chi-square
degrees of freedom =categories-1=4

c)

P-value < 0.005

d)

Since the P-value ≤ α, we reject the null hypothesis

e)

At the 5% level of significance, the evidence is  sufficient to conclude ….
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