Question

Assume that 64% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below, rounded to four decimal places:

a. There are some lefties (≥ 1) among the 5 people.

b. There are exactly 3 lefties in the group.

c. There are at least 4 lefties in the group.

d. There are no more than 2 lefties in the group.

e. How many lefties do you expect?

f. With what standard deviation?

Answer 1

This is a binomial distribution question with
n = 5
p = 0.64
q = 1 - p = 0.36
where

a) x = 1

b) x = 3

P(X = 3) = 0.3397
c) x = 4

d) x = 2

e) Since we know that

f)

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