After rejecting the null hypothesis of equal treatments, a researcher decided to compute a 95 percent confidence interval for the difference between the mean of treatment 1 and mean of treatment 2 based on the Tukey procedure. At α = .05, if the confidence interval includes the value of zero, then we can reject the hypothesis that the two population means are equal.
True
False
The error sum of squares measures the between-treatment
variability.
True
False
The experimentwise α for the 95 percent individual confidence interval for μ1 − μ2 (treatment mean 1 − treatment mean 2) will always be smaller than the experimentwise α for a Tukey 95 percent simultaneous confidence interval for μ1 − μ2.
True
False
In one-way ANOVA, a large value of F results when the within-treatment variability is large compared to the between-treatment variability.
True
False
False , this is not true that After rejecting the null hypothesis of equal treatments, a researcher decided to compute a 95 percent confidence interval for the difference between the mean of treatment 1 and mean of treatment 2 based on the Tukey procedure. At α = .05, if the confidence interval includes the value of zero, then we can reject the hypothesis that the two population means are equal.
True, The error sum of squares measures the between-treatment variability.
this is True , The experimentwise α for the 95 percent individual confidence interval for μ1 − μ2 (treatment mean 1 − treatment mean 2) will always be smaller than the experimentwise α for a Tukey 95 percent simultaneous confidence interval for μ1 − μ2.
true ,In one-way ANOVA, a large value of F results when the within-treatment variability is large compared to the between-treatment variability.
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