Question

A publisher reports that 54% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 110 found that 50% of the readers owned a laptop. Determine the P-value of the test statistic. Round your answer to four decimal places.

Answer 1

Solution :

Given that,

= 0.54

1 - = 0.46

n = 110

Point estimate = sample proportion = = x / n = 0.50

This a two- tailed test.

The null and alternative hypothesis is,

Ho: p = 0.54

Ha: p 0.54

Test statistics

z = ( - ) / *(1-) / n

= ( 0.50 - 0.54) / (0.54*0.46) /110

= -0.84

P-value = 2 * P(Z < z )

= 2 * ( P(Z < -0.84 ))

= 2 * 0.2005

= 0.4010