Question

Find the margin of error for the given values of​ c, sigma​, and n. cequals0.95​, sigmaequals3.3​, nequals100

Answer 1

Solution :

Given that,

Population standard deviation =    =3.3

Sample size n =100

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96   ( Using z table )

Margin of error = E = Z/2 * ( /n)

= 1.96 * ( 3.3/  100 )

E= 0.6468

Margin of error = E =0.6468