Question

Find the margin of error for the given values of c, sigma, and n. cequals0.95, sigmaequals3.3, nequals100

Answer #1

Solution :

Given that,

Population standard deviation =
=3.3

Sample size n =100

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96 ( Using z table )

Margin of error = E = Z/2
* (
/n)

= 1.96 * ( 3.3/ 100
)

E= 0.6468

Margin of error = E =0.6468

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Eequals= _ (Round to three decimal places as needed.)

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The margin of error is?
(Round to one decimal place as needed.)

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Assume that the preliminary sample has at least 30 members.
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