The director of special events for Sun City believed that the amount of money spent on fireworks displays on the 4th of July was predictive of attendance at the Fall Festival held in October. She gathered the following data to test her suspicion.
4th of July ($000) | Fall Festival (000) | 4th of July ($000) | Fall Festival (000) | ||||
9.5 | 7.2 | 9.0 | 9.5 | ||||
8.5 | 6.4 | 9.4 | 12.6 | ||||
11.4 | 11.4 | 7.5 | 6.6 | ||||
9.0 | 10.2 | 10.0 | 10.1 | ||||
5.5 | 6.0 | 6.0 | 6.1 | ||||
12.0 | 11.1 | 12.9 | 12.5 | ||||
8.0 | 7.5 | 13.5 | 11.8 | ||||
7.5 | 8.4 | ||||||
Determine the regression equation. (Round your answers to 3 decimal places.)
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Complete the given table. (Leave no cells blank - be certain to enter "0" wherever required. Round Coefficient, SE Coefficient, p-value to 3 decimal places and t to 2 decimal places.)
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Complete the ANOVA table. (Leave no cells blank - be certain to enter "0" wherever required. Round SS, MS, p-value to 3 decimal places and F to 2 decimal places.)
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Is the amount spent on fireworks related to attendance at the Fall Festival?
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The general regression is
y = a + b x
Where y - a dependent variable that is Fall festival
a - intercept
b - slope
x - an independent variable that is 4 th of July
By using excel the value of a and b can find out.
First, plug the values of x and y that is 4th July and Fall festival in the two columns of excel.
Step 1: Go in Data select Data analysis option
Step 2: Then select Regression and click ok.
Step 3: In input Y range select the values of y variable that is Fall festival.
Step 4: In input X range select the values of x variable that is 4th of July.
Step 5: Select output range and give anyone empty cell address from which the output will display.
Step 6: Click ok to see the regression output.
In the last table of output, there is a coefficient of intercept which is a and the coefficient of 4th of July is b that is a slope.
a = intercept = 1.230
b = slope = 0.851
The regression equation is,
Fall = 1.230 + 0.851 July
Coefficients, SE coefficient, t and P-values are given in the last output table in excel
Predictor | Coefficient | SE Coefficient | t | p-value |
Constant | 1.230 | 1.531 | 0.80 | 0.436 |
4th of July | 0.851 | 0.160 | 5.33 | 0.000 |
The second output table in excel is the ANOVA table
Source | DF | SS | MS | F | p-value |
Regression | 1 | 55.941 | 55.941 | 28.43 | 0.000 |
Residual | 13 | 25.575 | 1.967 | ||
Total | 14 | 81.516 |
The P-value across to the slope is too small, so the relationship is significant.
There is a relationship between attendance at the Fall festival and the fireworks.
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