Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient's total calcium tests gave the following readings (in mg/dl). Assume that the population of x values has an approximately normal distribution.
10.1 | 9.4 | 10.7 | 9.5 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |
(a) Use a calculator with mean and sample standard deviation keys to find the sample mean reading x and the sample standard deviation s. (Round your answers to two decimal places.)
x = | mg/dl |
s = | mg/dl |
(b) Find a 99.9% confidence interval for the population mean of
total calcium in this patient's blood. (Round your answer to two
decimal places.)
lower limit | mg/dl |
upper limit | mg/dl |
(c) Based on your results in part (b), do you think this patient
still has a calcium deficiency? Explain.
Yes. This confidence interval suggests that the patient may still have a calcium deficiency.Yes. This confidence interval suggests that the patient no longer has a calcium deficiency. No. This confidence interval suggests that the patient may still have a calcium deficiency.No. This confidence interval suggests that the patient no longer has a calcium deficiency.
a. Sample mean is
Create the following table.
data | data-mean | (data - mean)2 |
10.1 | -0.11 | 0.0121 |
9.4 | -0.81 | 0.6561 |
10.7 | 0.49 | 0.2401 |
9.5 | -0.71 | 0.5041 |
9.4 | -0.81 | 0.6561 |
9.8 | -0.41 | 0.1681 |
10.0 | -0.21 | 0.0441 |
9.9 | -0.31 | 0.0961 |
11.2 | 0.99 | 0.9801 |
12.1 | 1.89 | 3.5721 |
Find the sum of numbers in the last column to get.
So standard deviation is
b. t value is TINV(0.001,9)=4.781
So Margin of Error is
So CI is
c. As Upper and lower CI is greater than 6.
So answer here is Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.
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