In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2531 subjects randomly selected from an online group involved with ears. 1161 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. LOADING... Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. nothing
A point estimate of apopulation parameter is a single value of a statistic. For example, the sample mean x is a point estimate of thepopulation mean μ. Similarly, the sample proportion p is a point estimate of the population proportion P.
Here P=1161/2531=0.46 is a point estimate.
Also we calculate 99% confidence interval from given data.
Since alpha=0.01then z value is
zα/2 = 2.5758293064
Lower Bound = p̂ - zα/2•√p̂(1 - p̂)/n = 0.46 -
(2.5758293064)(0.009906716230504955) = 0.43448199
Upper Bound = p̂ + zα/2•√p̂(1 - p̂)/n = 0.46 +
(2.5758293064)(0.009906716230504955) = 0.48551801
Confidence Interval = (0.43448199, 0.48551801)
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