Question

3. Interval estimation of a population mean, population standard deviation unknown The Business Environment and Enterprise...

3. Interval estimation of a population mean, population standard deviation unknown

The Business Environment and Enterprise Performance Survey (BEEPS), developed by the European Bank for Reconstruction and Development and the World Bank, is a survey of more than 4,000 firms in 22 transition countries. Conducted in 2000, BEEPS gathered information on the impediments to business growth in transition countries.

As part of BEEPS, firms that import goods answered the question, “How many days does it take from the time your goods arrive in their port of entry until the time you can claim them from customs?” For the sample of 43 importing firms in Slovakia, the sample mean x̄ was 4.8 days, and the sample standard deviation s was 8.2 days.

The standard deviation of the population distribution is unknown, but you are willing to assume that the population distribution is not highly skewed and contains no outliers.

To develop a 99% confidence interval estimate of the mean number of days it takes for imported goods to clear customs in Slovakia, use the:

a. t distribution with 42 degrees of freedom

b. t distribution with 35 degrees of freedom

c. standard normal distribution

d. t distribution with 43 degrees of freedom

Use the Distributions tool to compute a 99% confidence interval estimate for the mean number of days it takes for imported goods to clear customs in Slovakia.

You are 99% confident that the mean wait time for imported goods to clear customs in Slovakia is between:

a. 1.43

b. 4.29

c. 1.78

d. 1.58

and:

a. 8.02

b. 5.31

c. 8.17

d. 7.82

days.

The confidence interval estimate you calculated is appropriate because:

a. You are assuming the population distribution is not highly skewed nor contains outliers and the sample size is at least 30.

b. The wait time for imported goods to clear customs in Slovakia is normally distributed.

c. Using the t distribution means the sampling distribution of the mean does not need to be normal.

Homework Answers

Answer #1

a. t distribution with 42 degrees of freedom

sample mean 'x̄= 4.800
sample size   n= 43.00
sample std deviation s= 8.20
std error 'sx=s/√n= 1.2505
for 99% CI; and 42 df, value of t= 2.6980
margin of error E=t*std error    = 3.374
lower bound=sample mean-E = 1.426
Upper bound=sample mean+E = 8.174

You are 99% confident that the mean wait time for imported goods to clear customs in Slovakia is between   1.43 and 8.17

a. You are assuming the population distribution is not highly skewed nor contains outliers and the sample size is at least 30.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The Business Environment and Enterprise Performance Survey (BEEPS), developed by the European Bank for Reconstruction and...
The Business Environment and Enterprise Performance Survey (BEEPS), developed by the European Bank for Reconstruction and Development and the World Bank, is a survey of more than 4,000 firms in 22 transition countries. Conducted in 2000, BEEPS gathered information on the impediments to business growth in transition countries. As part of BEEPS, firms answered the question, How many days does the preshipment inspection take from the time you submit your goods until the time they are released? For the sample...
1. To estimate the mean of a population with unknown distribution shape and unknown standard deviation,...
1. To estimate the mean of a population with unknown distribution shape and unknown standard deviation, we take a random sample of size 64. The sample mean is 22.3 and the sample standard deviation is 8.8. If we wish to compute a 92% confidence interval for the population mean, what will be the t multiplier? (Hint: Use either a Probability Distribution Graph or the Calculator from Minitab.)
7. If I have a population of an unknown mean and unknown standard deviation, what is...
7. If I have a population of an unknown mean and unknown standard deviation, what is the 95% confidence interval estimate of the mean if a. A random sample of size 25 gives a mean of 50 and a standard deviation of 12 b. A random sample of size 16 gives a mean of 50 and a standard deviation of 12 8. The average cost per night of a hotel room in New York City is $325. Assume this estimate...
a. If the confidence interval for the standard deviation is between 9 and 16 then the...
a. If the confidence interval for the standard deviation is between 9 and 16 then the confidence interval for a variance will be between 81 and 256 9 and 16 3 and 4 -3 and -4 b. In a study of size 8 where the variance is unknown, and the population is normally distributed, the distribution that should be used to calculate confidence intervals is a normal distribution a t distribution with 7 degrees of freedom a t distribution with...
When constructing a confidence interval estimate for a population mean​ (when the standard deviation of the...
When constructing a confidence interval estimate for a population mean​ (when the standard deviation of the population is​ known), what is the calculation that has to be made to obtain the error​ margin? A. You multiply the number of standard deviations by the standard deviation of the sampling distribution of sample means. B. You subtract the sample mean from the population mean and then divide by the standard deviation of the population. C. You divide the standard deviation of the...
A certain test has a population mean (mu) of 285 with a population standard deviation (sigma)...
A certain test has a population mean (mu) of 285 with a population standard deviation (sigma) or 125. You take an SRS of size 400 find that the sample mean (x-bar) is 288. The sampling distribution of x-bar is approximately Normal with mean: The sampling distribution of x-bar is approximately Normal with standard deviation: Based on this sample, a 90% confidence interval for mu is: Based on this sample, a 95% confidence interval for mu is: Based on this sample,...
A 99% confidence interval estimate of the population mean ? can be interpreted to mean: a)...
A 99% confidence interval estimate of the population mean ? can be interpreted to mean: a) if all possible sample are taken and confidence intervals created, 99% of them would include the true population mean somewhere within their interval. b) we have 99% confidence that we have selected a sample whose interval does include the population mean. c) we estimate that the population mean falls between the lower and upper confidence limits, and this type of estimator is correct 99%...
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 45 business​ days, the mean closing price of a certain stock was ​$116.70. Assume the population standard deviation is ​$11.02. The​ 90% confidence interval is ​( ​, ​). Construct the indicated confidence interval for the population mean μ...
Suppose scores exams in statistics with an unknown population mean and a sample standard deviation of...
Suppose scores exams in statistics with an unknown population mean and a sample standard deviation of 2 points. A random sample of 16 scores is taken and gives a sample mean. (sample mean score) of 8. Find the confidence interval estimate for the population mean test score ( the mean score of all tests). Find a 90% confidence interval for the true (population) mean of statistics test scores.
Given the sample mean, x, the assumed population mean, μ, the sample standard deviation,s, and the...
Given the sample mean, x, the assumed population mean, μ, the sample standard deviation,s, and the sample size, n, what is the formula to compute the t-statistic for our sample mean? In other words, what is the t-score in “the x distribution”? What is the number of degrees of freedom?