Question

The mean cost of a five pound bag of shrimp is 42 dollars with a variance of 49.

If a sample of 54  bags of shrimp is randomly selected, what is the probability that the sample mean would differ from the true mean by more than 1.4  dollars? Round your answer to four decimal places.

Answer 1

This is a normal distribution question with

Sample size (n) = 54

Since we know that


probability that the sample mean would differ from the true mean by more than 1.4  dollars means
we need to find the probability for the sample mean to lie outside

x1 = 40.6
x2 = 43.4

This implies that

PS: you have to refer z score table to find the final probabilities.

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