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A random sample of 10 children found that the average growth for the first year was 9.8 inches. The sample standard deviation was 0.96 inches. Find the 95% confidence interval for the true mean.
The lower bound of the interval is ___________
The upper bound of the interval is ___________
Round to 4 decimal places.
df = n - 1 = 10 - 1 = 9
From T table,
t critical value at 0.05 significance level with 9 df = 2.262
95% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
9.8 - 2.262 * 0.96 / sqrt(10) < < 9.8 + 2.262 * 0.96 / sqrt(10)
9.1133 < < 10.4867
Lower bound = 9.1133
Upper bound = 10.4867
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