Find the margin of error for the given values of c,
sigmaσ,
and n.
cequals=0.950.95,
sigmaσequals=2.82.8,
nequals=64
Solution :
Given that,
Population standard deviation =
= 2.8
Sample size n =64
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 1.96 * ( 2.8 /
64)
E= 0.6860
Get Answers For Free
Most questions answered within 1 hours.