Among 12 calculator, 4 of them are defected. If we randomly choose 2 calculators, find the probability of getting at least 1 defected calculator
Total number of ways in which 2 calculators can be taken from 12 is
There are 4 Defective and 12-4=8 non defective
Number of ways in which one defective and one non defective is chosen =4*8=32
Also number of ways in which two defective are chosen is
Thus total number of ways in which at least one defective calculator can be chosen is 32+6=38
Hence the required probability is
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