A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.9 years, and standard deviation of 1.2 years. If 7 items are picked at random, 5% of the time their mean life will be less than how many years? Give your answer to one decimal place.
Solution :
Given that,
mean = = 3.9
standard deviation = = 1.2
Using standard normal table ,
n = 7
= 3.9
= / n = 1.2 / 7 = 0.4536
P(Z < z) = 5%
P(Z < -1.65) = 0.05
z = -1.65
= z * + =-1.65 * 0.4536 + 3.9 = 3.2
The time their mean life will be less than 3.2 years
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