A cell phone company offers two plans to its subscribers. At the time new subscribers sign up, they are asked to provide some demographic information. The mean yearly income for a sample of 38 subscribers to Plan A is $58,500 with a standard deviation of $8,000. This distribution is positively skewed; the coefficient of skewness is not larger. For a sample of 42 subscribers to Plan B, the mean income is $59,100 with a standard deviation of $9,500. At the 0.02 significance level, is it reasonable to conclude the mean income of those selecting Plan B is larger?
a. State the decision rule. (Negative answer should be indicated by a minus sign. Round the final answer to 3 decimal places.)
Reject H0 if t > _________ -1.665 Incorrect.
b. Compute the value of the test statistic. (Negative answer should be indicated by a minus sign. Round the final answer to 3 decimal places.)
Value of the test statistic _______ -0.306, -0.312 Incorrect.
Please note the incorrect answers. Thank you.
Answer)
A)
Plan A : u1 = 58500, s1 = 8000, n1 = 38
Plan B : u2 = 59100, S2= 9500, n2= 42
Ho : u2 = u1
Ha : u2>u1
From t table, for degrees of freedom smaller of n11-, n2-1, in this case 37 and significance level of 0.02
Critical value t = 2.129
Decision rule is if t > 2.129, reject Ho.
B)
Test statistics t = (u2-u1)/sqrt(s2p/n1 + s2p/n2)
s2p=(n1-1* s21+ n2-1* s22)/(n1+n2-2)
Sp^2 = 77798076.923076
t = 0.304
As the obtained t is not greater than the critical value 2.129, we fail to reject the Ho
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