Question

Weights of female cats of a certain breed are normally distributed with mean 4.3 kg and standard deviation 0.6 kg.

6 cats are chosen at random. What is the probability that exactly one of them weighs more than 4.5 kg?

Answer 1

Solution :

Given that ,

mean = = 4.3

standard deviation = = 0.6

= / n = 0.6 / 6 = 0.2449

P( > 4.5) = 1 - P( < 4.5)

= 1 - P[( - ) / < (4.5 - 4.3) / 0.2449]

= 1 - P(z < 0.8167)

= 1 - 0.7929

= 0.2071

Probability = 0.2071