Given a normal distribution with μ = 101 and σ = 15, and given you select a sample of n=9, complete parts (a) through (d).
What is the probability that Upper X overbar is less than 95?
Solution :
Given that ,
mean = = 101
standard deviation = = 15
n = 9
= 101
= / n = 15 / 9=5
P( < 95) = P[( - ) / < (95 -101) / 5]
= P(z <-1.2 )
Using z table
= 0.1151
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