Now calculate what percentile Cassie’s score lies.
(1) Given that mean = 70 and standard deviation = 5
x value for Chris is 60
z score = (x-mean)/standard deviation = (60-70)/5 = -10/5 = -2
Chris score is 2 standard deviations below the mean exam score.
(2) Given that mean = 70 and standard deviation = 5
x value for Cassie is 85
z score = (x-mean)/standard deviation = (85-70)/5 = 15/5 = 3
Cassie score is 3 standard deviations above the mean exam score.
(3) Confidence interval is given as
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