Question

1. Suppose that the average grades of an introduction to marketing course final is 70 with...

1. Suppose that the average grades of an introduction to marketing course final is 70 with a standard deviation of 5. Chris got 60 in this exam, please calculate Chris’ z-score. How do we interpret that number?

2. Cassie got 85 in this exam, please calculate Cassie’s z-score. How do we interpret that number?

Now calculate what percentile Cassie’s score lies.

3. Find the interval of scores within which 95% of the students fall (z-score = ±1.96) in this exam.


Homework Answers

Answer #1

(1) Given that mean = 70 and standard deviation = 5

x value for Chris is 60

z score = (x-mean)/standard deviation = (60-70)/5 = -10/5 = -2

Chris score is 2 standard deviations below the mean exam score.

(2) Given that mean = 70 and standard deviation = 5

x value for Cassie is 85

z score = (x-mean)/standard deviation = (85-70)/5 = 15/5 = 3

Cassie score is 3 standard deviations above the mean exam score.

(3) Confidence interval is given as

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