Given that X is a normally distributed random variable with a mean of 50 and a standard deviation of 2, find the probability that X is between 47 and 54.
0.7104 |
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0.6680 |
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0.9772 |
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0.9104 |
Solution :
Given that ,
mean = = 50
standard deviation = = 2
P(47< x <54 ) = P[(47-50) /2 < (x - ) / < (54-50) /2 )]
= P( -1.5< Z <2 )
= P(Z < 2) - P(Z < -1.5)
Using z table
= 0.9772 -0.0668
=0.9104
probability= 0.9104
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