Question

The director of research and development is testing a new medicine. She wants to know if there is evidence at the 0.02 level that the medicine relieves pain in more than 332 seconds. For a sample of 60 patients, the mean time in which the medicine relieved pain was 335 seconds. Assume the population standard deviation is 20. Find the P-value of the test statistic.

Answer 1

Solution :

The null and alternative hypothesis is ,

H₀ :   = 332

H_a : > 332

= 335

= 20

n = 60

= 0.02

Test statistic = z =

= ( - ) / / n

= (335 - 332) / 20 / 60

Test statistic = z = 1.16

p(Z > 1.16 ) = 1-P (Z < 1.16) = 1 - 0.8770

P-value = 0.1230

Fail to rejected null hypothesis because p-value > 0.02