Question

A report gave the following information on births in a certain country during a particular year.

Type of Birth	Number of Births
Single birth	3,868,214
Twins	125,336
Triplets	4,233
Quadruplets	266
Quintuplets or higher	47

(a)

Use this information to estimate the probability that a randomly selected pregnant woman who gave birth in this year delivered twins. (Round your answer to three decimal places.)

(b)

Use this information to estimate the probability that a randomly selected pregnant woman who gave birth in this year delivered quadruplets. (Round your answer to six decimal places.)

(c)

Use this information to estimate the probability that a randomly selected pregnant woman who gave birth in this year gave birth to more than a single child. (Round your answer to three decimal places.)

Answer 1

Total number of births = 3868214 + 125336 + 4233+266+47 = 3998096

a) P( that a randomly selected pregnant woman who gave birth in this year delivered twins) = 125336 / 3998096

= 0.0313

b) P( that a randomly selected pregnant woman who gave birth in this year delivered quadruplets)

= 266 / 3998096

  = 0.000066

c) P( that a randomly selected pregnant woman who gave birth in this year gave birth to more than a single child)

= 1- P( gave birth to single child)

= 1- (3868214/ 3998096)

= 1- 0.967

= 0.032