The amount of tea leaves in a can from a particular production line is normally distributed with µ = 110 grams and σ = 25 grams. A sample of 25 cans is to be selected. What is the probability that the sample mean will be less than 100 grams?
Solution :
Given that ,
mean = = 110
standard deviation = = 25
= / n = 25 / = 25 = 5
P( < 100) = P(( - ) / < (100 - 110) / 5)
= P(z <-2 )
= 0.0228
Probability= 0.0228
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