A survey of an urban university showed that 850 of 1,000 students sampled supported a fee increase to fund improvements to the student recreation center.
a. What is the point estimate for the proportion of students who supported the fee increase? b. Using the 0.90 level of confidence, construct the confidence interval for the population proportion. c. If university officials say that at least 85% of the voting student population need to support the fee increase (to be applied), what conclusion can be drawn, based on a 0.90 level of confidence? Explain.
given data are:-
sample size(n) = 1000
x = number of students who supported a fee increase to fund improvements to the student recreation center.
a). the point estimate for the proportion of students who supported the fee increase is:-
b). z critical value for 90% confidence level, both tailed test be:-
The 95% confidence interval for the population proportion is:-
c).The interval estimate contains 0.85..so we can say that at least 85% of the voting student population supports the fee increase at 0.90 confidence level .
[ hypothesis:-
as 0.85 in contained in the 90% confidence interval , we fail to reject the null hypothesis]
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