Question

Ralph’s bowling scores in a single game are normally distributed with a mean of 120 and a standard deviation of 10.

1. He plays 5 games. What is the mean and standard deviation of his total score?
2. What is the mean and standard deviation of Ralph’s average score for the 5 games?

Answer 1

This is a normal distribution question with

Sample size (n) = 5
a) Since we know that
(cX) = c.(X)
(5X) = 5*120 = 600
Also
Var(cX) = c2.Var(X)
(cX) = c.(X)
(5X) = 5*10 = 50

b) Since we know that



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