The final exam in a certain course has scores that are normally distributed with a mean of 82.4 with a standard deviation of 5.9. If 23 students are randomly selected, find the probability that the mean of their final exam scores is less than 84. Round your answer 4 places after the decimal point.
Solution :
Given that ,
mean = = 82.4
standard deviation = = 5.9
n = 23
= 82.4
= / n = 5.9/ 23=1.23
P( <84 ) = P[( - ) / < (84-82.4) / 1.23]
= P(z <1.30 )
Using z table
= 0.9032
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