You want to rent an unfurnished one-bedroom apartment for next semester. You take a random sample of 10 apartments advertised in the local newspaper and record the rental rates. Here are the rents (in dollars per month).
645, 340, 515, 455, 530, 655, 320, 465, 435, 615
Find a 95% confidence interval for the mean monthly rent for unfurnished one-bedroom apartments available for rent in this community.
First let us find sample mean
Create the following table.
data | data-mean | (data - mean)2 |
645 | 147.5 | 21756.25 |
340 | -157.5 | 24806.25 |
515 | 17.5 | 306.25 |
455 | -42.5 | 1806.25 |
530 | 32.5 | 1056.25 |
655 | 157.5 | 24806.25 |
320 | -177.5 | 31506.25 |
465 | -32.5 | 1056.25 |
435 | -62.5 | 3906.25 |
615 | 117.5 | 13806.25 |
Find the sum of numbers in the last column to get.
So standard deviation is
Let us assume distribution is normal
t value is TINV(0.05,9)=2.262
So Margin of Error is
Hence CI is
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