Question

In a survey of men in a certain country​ (ages 20minus−​29), the mean height was 62.862.8...

In a survey of men in a certain country​ (ages 20minus−​29), the mean height was 62.862.8 inches with a standard deviation of 2.72.7 inches. ​(a) What height represents the 9898th ​percentile? ​(b) What height represents the first​ quartile?

Round to two decimal places as needed

Homework Answers

Answer #1

find z score for corresponding 98th Percentile (0.98) and first quartile 0.25

z score of 0.98 = 2.326

z score for 0.25 = -0.67

The mean increased by the product of z score and the standard deviation:

​(a) What height represents the 98th ​percentile?

x = μ +zσ

x = 62.8+2.326*2.7 = 69.08

​(b) What height represents the first​ quartile?

x = μ +zσ

x = 62.8-0.67*2.7 = 60.99

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