Question

Find the critical value

t/α2

needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places.

(a) For level

99.5%

and sample size

6

(b) For level

95%

and sample size

15

(c) For level

80%

and sample size

29

(d) For level

98%

and sample size

12

Answer #1

solution

Degrees of freedom = df = n - 1 = 6- 1 = 5

At 95.5% confidence level the t is ,

= 1 - 99.5% = 1 - 0.995 = 0.005

/ 2= 0.005 / 2 = 0.0025

t
/2,df = t0.0025,5 = **4.772** ( using student t
table)

b.

n = Degrees of freedom = df = n - 1 =15 - 1 = 14

At 95% confidence level the t is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2= 0.05 / 2 = 0.025

t
/2,df = t0.025,14 = **2.145** ( using student t
table)

c.

n = Degrees of freedom = df = n - 1 =29 - 1 = 28

At 80% confidence level the t is ,

= 1 - 80% = 1 - 0.80 = 0.20

/ 2= 0.20 / 2 = 0.10

t /2,df = t0.10,28 =1.313 ( using student t table)

d.

Degrees of freedom = df = n - 1 =12 - 1 = 11

At 98% confidence level the t is

= 1 - 98% = 1 - 0.98 = 0.02

/ 2 = 0.02/ 2 = 0.01

t
/2,df = t0.01,11 = **2.718** ( using student t
table)

Find the critical value
t/α2
needed to construct a confidence interval of the given level
with the given sample size. Round the answers to three decimal
places.
Part 1 of 4
(a) For level
99%
and sample size
5
Part 2 of 4
(b) For level
90%
and sample size
14
Part 3 of 4
(c) For level
99.5%
and sample size
28
Part 4 of 4
(d) For level
95%
and sample size
11

Find the critical value t a/2 needed to construct a confidence
interval of the given level with th sample size. Round the amswers
to theee decimal places.
For level 95% and sample size 11?
For level 98% and sample size 26?
For level 99% and sampke size 12?

1) Find the critical value t (a/2) needed to construct a
confidence interval of the given level with the given sample size.
Round the answers to three decimal places
a) 98% sample size 11
critical value-
b) for level 95% and sample size 25
critical value-
c)for level 99% and sample size 14
2) a sample of size n equals 45 has a sample mean X equals 56.9
and sample standard deviation s equals 9.4.
construct a 99% confidence interval...

1.Find the critical value tα/2 needed to construct a
confidence interval of the given level with given sample
size.
Level 90%, sample size 21
Group of answer choices
1.725
1.325
1.721
1.645
2.
Find the probability P(-0.62 < z < -0.01) using the
standard normal distribution.
Group of answer choices
0.2284
0.3584
0.7716
0.1900

Use Table A.3 to find the critical value 2
ta/2 needed to construct a confidence interval
of the given level with the given sample size:
a. Level 99%, sample size 19
b. Level 90%, sample size 172

Determine the t critical value for a two-sided
confidence interval in each of the following situations. (Round
your answers to three decimal places.)
(a) Confidence level = 95%, df = 5
(b) Confidence level = 95%, df = 15
(c) Confidence level = 99%, df = 15
(d) Confidence level = 99%, n = 10
(e) Confidence level = 98%, df = 21
(f) Confidence level = 99%, n = 34

Construct a confidence interval of the population proportion at
the given level of confidence.
x=540, n=1100, 95% confidence
The lower bound of the confidence interval is _______.
(Round to three decimal places as needed.)
The upper bound of the confidence interval is_______.
(Round to three decimal places as needed.)

Find the confidence interval for the given values of ?, ?, ?⎯⎯⎯,
and confidence level, using the t distribution.
?=19.2, ?=29, ?⎯⎯⎯=71, confidence = 0.81
Enter your answer by filling in the blanks ( ____ , ____ ).
Round final answers to 2 decimal places.

Find the following critical t-scores used in an 88% confidence
interval for a population mean when the population’s standard
deviation (σσ) is unknown. Give each answer to at least three
decimal places.
The t-critical value for an 88% confidence interval with sample
size 38 is:
The t-critical value for an 88% confidence interval with sample
size 48 is:
The t-critical value for an 88% confidence interval with sample
size 64 is:
The t-critical value for an 88% confidence interval with...

Construct a confidence interval of the population proportion at
the given level of confidence.x=120, n=1100, 94% confidence.
The lower bound of the confidence interval is:
(Round to three decimal places as needed.)
The upper bound of the confidence interval is:
(Round to three decimal places as needed.)

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