Question

A baseball player has a lifetime batting average of 0.168. If, in a season, this player has 460 "at bats", what is the probability he gets 101 or more hits?

Probability of 101 or more hits = ?

Answer 1

Solution :

Given that,

Using binomial distribution,

= n * p = 460 * 0.168 = 77.28

= n * p * q = 460 * 0.168 * 0.832 = 8.01854

Using continuity correction ,

P(x > 100.5) = 1 - P(x < 100.5)

= 1 - P((x - ) / < (100.5 - 77.28) / 8.01584)

= 1 - P(z < 2.90)

= 0.0019

Probability of 101 or more hits = 0.0019